Question

1. complete the noble gas notation for the following element: e. selenium

Explanation:

Step1: Determine the nearest noble gas before selenium

Selenium has an atomic number of 34. The nearest noble - gas with a lower atomic number is argon (Ar) which has an atomic number of 18.

Step2: Write the electron configuration after argon

The remaining electrons are \(34 - 18=16\). The electron - configuration after argon is \(4s^{2}3d^{10}4p^{4}\).

Answer:

\([Ar]4s^{2}3d^{10}4p^{4}\)