Question

1. find the sum.

$4\frac{2}{3} + 3\frac{2}{3}$
a. $1\frac{2}{3}$
b. $6\frac{2}{3}$
c. $7\frac{1}{3}$
d. $8\frac{1}{3}$

1. find the sum.

$3\frac{4}{5} + 6\frac{2}{5}$
a. $9\frac{1}{5}$
b. $9\frac{6}{10}$
c. $10\frac{1}{5}$
d. $10\frac{6}{5}$

Explanation:

Step1: Add whole numbers

$4 + 3 = 7$

Step2: Add fractional parts

$\frac{2}{3} + \frac{2}{3} = \frac{4}{3}$

Step3: Simplify improper fraction

$\frac{4}{3} = 1\frac{1}{3}$

Step4: Sum total values

$7 + 1\frac{1}{3} = 8\frac{1}{3}$

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Step1: Add whole numbers

$3 + 6 = 9$

Step2: Add fractional parts

$\frac{4}{5} + \frac{2}{5} = \frac{6}{5}$

Step3: Simplify improper fraction

$\frac{6}{5} = 1\frac{1}{5}$

Step4: Sum total values

$9 + 1\frac{1}{5} = 10\frac{1}{5}$

Answer:

1. D. $8\frac{1}{3}$
2. C. $10\frac{1}{5}$