Question

1. -/1 points details fill in the blank. let ( \theta ) be an angle in standard position with ( (x, y) ) a point on the terminal side of ( \theta ) and ( r = sqrt{x^2 + y^2}

eq 0 ). ( \tan(\theta) = square ) resources read it

Explanation:

Step1: Recall the definition of tangent in standard position

In the standard position of an angle $\theta$, if a point $(x, y)$ lies on the terminal side of $\theta$ and $r = \sqrt{x^2 + y^2}
eq0$, the tangent of the angle is defined as the ratio of the $y$-coordinate to the $x$-coordinate.

Step2: Write the formula for $\tan(\theta)$

From the definition, we know that $\tan(\theta)=\frac{y}{x}$ (where $x
eq0$).

Answer:

$\frac{y}{x}$