Question

if 8.1e25 molecules of co₂ are produced in a combustion reaction, what is the mass (in kg) of co₂ that is produced?

Explanation:

Step1: Find moles of \(CO_2\)

Use Avogadro's number (\(6.022\times10^{23}\) molecules/mol). Moles (\(n\)) = \(\frac{\text{number of molecules}}{N_A}\) = \(\frac{8.1\times10^{25}}{6.022\times10^{23}}\) ≈ 134.5 mol.

Step2: Calculate molar mass of \(CO_2\)

Molar mass of \(C\) = 12.01 g/mol, \(O\) = 16.00 g/mol. So \(M(CO_2)\) = 12.01 + 2×16.00 = 44.01 g/mol.

Step3: Find mass in grams

Mass (\(m\)) = \(n\times M\) = 134.5 mol × 44.01 g/mol ≈ 5919 g.

Step4: Convert to kilograms

\(5919\) g = \(\frac{5919}{1000}\) kg ≈ 5.9 kg.

Answer:

Approximately 5.9 kg