Question

1. if a rectangle measures 20 meters by 48 meters, what is the length, in meters, of the diagonal of the rectangle? f. 52 g. 68 h. 72 j. 112 k. 2,704

Explanation:

Step1: Apply Pythagorean theorem

For a rectangle, diagonal $d$ satisfies $d^2 = l^2 + w^2$, where $l=48$ m, $w=20$ m.
$d^2 = 48^2 + 20^2$

Step2: Calculate squared side lengths

$48^2 = 2304$, $20^2 = 400$
$d^2 = 2304 + 400 = 2704$

Step3: Find square root of sum

$d = \sqrt{2704}$

Answer:

F. 52