Question

1. a motorcycle engine converts 470,000 j of chemical energy into 76,000 j of kinetic energy. how efficient is the engine? round to the nearest percent.

17%
16%
15%
25%

Explanation:

Step1: Define efficiency formula

Efficiency = $\frac{\text{Useful Output Energy}}{\text{Total Input Energy}} \times 100\%$

Step2: Plug in given values

Efficiency = $\frac{76000}{470000} \times 100\%$

Step3: Calculate and round

$\approx 0.1617 \times 100\% = 16\%$ (rounded to nearest percent)

Answer:

16%