Question

23.

1. (assume the triangle below is equilateral.)

directions: find the area of each figure below.
25.

26.

Explanation:

Step1: Area of right triangle

Area = $\frac{1}{2} \times \text{base} \times \text{height}$
$\frac{1}{2} \times 3mn^2 \times 4m^2 = 6m^3n^2$

Step2: Area of equilateral triangle

Area = $\frac{1}{2} \times \text{base} \times \text{height}$
$\frac{1}{2} \times 8mn \times 4m^2 = 16m^3n$

Step3: Area of trapezoid

Area = $\frac{1}{2} \times (\text{top base} + \text{bottom base}) \times \text{height}$
$\frac{1}{2} \times (7a^2b + 11a^2b) \times 3ab = \frac{1}{2} \times 18a^2b \times 3ab = 27a^3b^2$

Step4: Area of circle

Area = $\pi r^2$
$\pi (3x^3y)^2 = 9\pi x^6y^2$

Answer:

1. $6m^3n^2$
2. $16m^3n$
3. $27a^3b^2$
4. $9\pi x^6y^2$