Question

1. $\frac{6}{12} div \frac{2}{6} = \frac{6}{12} div \frac{}{12}$
2. $\frac{8}{14} div \frac{7}{14}$
3. $\frac{8}{14} div \frac{1}{2} = \frac{8}{14} div \frac{}{14}$
4. $\frac{11}{14} div \frac{2}{14}$
5. $\frac{11}{14} div \frac{1}{7} = \frac{11}{14} div \frac{}{14}$
6. $\frac{1}{7} div \frac{6}{14} = \frac{}{14} div \frac{6}{14}$
7. $\frac{7}{18} div \frac{3}{18}$
8. $\frac{7}{18} div \frac{1}{6} = \frac{7}{18} div \frac{}{18}$
9. $\frac{1}{3} div \frac{12}{18} = \frac{}{18} div \frac{12}{18}$
10. $\frac{1}{6} div \frac{4}{18}$
11. $\frac{4}{12} div \frac{8}{6}$
12. $\frac{1}{3} div \frac{3}{15}$
13. $\frac{2}{6} div \frac{1}{9} = \frac{}{18} div \frac{}{18}$
14. $\frac{1}{6} div \frac{4}{9}$
15. $\frac{2}{3} div \frac{3}{4}$
16. $\frac{1}{3} div \frac{3}{5}$
17. $\frac{1}{7} div \frac{1}{2}$
18. $\frac{5}{} div \frac{2}{}$ (partially visible)

Explanation:

Let's solve problem 25: $\frac{8}{14} \div \frac{7}{14}$

Step1: Recall fraction division rule

To divide fractions, we multiply the first fraction by the reciprocal of the second fraction. So, $\frac{a}{b} \div \frac{c}{d} = \frac{a}{b} \times \frac{d}{c}$.
For $\frac{8}{14} \div \frac{7}{14}$, the reciprocal of $\frac{7}{14}$ is $\frac{14}{7}$.
So, $\frac{8}{14} \div \frac{7}{14} = \frac{8}{14} \times \frac{14}{7}$

Step2: Simplify the multiplication

The 14 in the numerator and denominator cancels out. So we have $\frac{8}{1} \times \frac{1}{7} = \frac{8}{7}$ (or $1\frac{1}{7}$)

Answer:

$\frac{8}{7}$ (or $1\frac{1}{7}$)