Question

1. complete the table. then analyze the data to determine if compounds i and ii are the same compound. if the compounds are different, use the law of multiple proportions to show the relationship between them. analysis data of two iron compounds compound total mass (g) mass fe (g) mass o (g) mass percent fe mass percent o i 75.00 52.46 22.54 ii 56.00 43.53 12.47

Explanation:

Step1: Calculate mass percent of Fe in Compound I

Mass percent of Fe in Compound I = $\frac{\text{Mass of Fe in Compound I}}{\text{Total mass of Compound I}}\times100\%=\frac{52.46}{75.00}\times 100\%\approx 69.95\%$

Step2: Calculate mass percent of O in Compound I

Mass percent of O in Compound I = $\frac{\text{Mass of O in Compound I}}{\text{Total mass of Compound I}}\times100\%=\frac{22.54}{75.00}\times 100\%\approx 30.05\%$

Step3: Calculate mass percent of Fe in Compound II

Mass percent of Fe in Compound II = $\frac{\text{Mass of Fe in Compound II}}{\text{Total mass of Compound II}}\times100\%=\frac{43.53}{56.00}\times 100\%\approx 77.73\%$

Step4: Calculate mass percent of O in Compound II

Mass percent of O in Compound II = $\frac{\text{Mass of O in Compound II}}{\text{Total mass of Compound II}}\times100\%=\frac{12.47}{56.00}\times 100\%\approx 22.27\%$

Step5: Determine if they are the same compound

Since the mass - percent compositions of Fe and O in the two compounds are different, they are different compounds.

Step6: Apply law of multiple proportions

For a fixed mass of Fe (say 1 g of Fe), in Compound I, mass of O per 1 g of Fe = $\frac{22.54}{52.46}\approx0.43$ g. In Compound II, mass of O per 1 g of Fe = $\frac{12.47}{43.53}\approx0.29$ g. The ratio of the mass of O in Compound I to the mass of O in Compound II for the same mass of Fe is $\frac{0.43}{0.29}\approx\frac{3}{2}$, which is a simple whole - number ratio as per the law of multiple proportions.

Answer:

Compound	Total Mass (g)	Mass Fe (g)	Mass O (g)	Mass Percent Fe	Mass Percent O
II	56.00	43.53	12.47	77.73%	22.27%

The compounds are different. The ratio of the mass of O in Compound I to the mass of O in Compound II for the same mass of Fe is approximately 3:2, following the law of multiple proportions.