Question

a 0.25 kg baseball is in contact with a bat for 0.0075 s and exerts a force of 18,500 n. what impulse is delivered to the ball?
o 33 kg·\\(\frac{m}{s}\\)
o 140 kg·\\(\frac{m}{s}\\)
o 4600 kg·\\(\frac{m}{s}\\)
o 74,000 kg·\\(\frac{m}{s}\\)

Explanation:

Step1: Recall impulse - force formula

The formula for impulse $J$ is $J = F\times\Delta t$, where $F$ is the force and $\Delta t$ is the time interval.

Step2: Substitute given values

Given $F = 18500\ N$ and $\Delta t=0.0075\ s$. Then $J=18500\times0.0075$.

Step3: Calculate the impulse

$J = 18500\times0.0075=138.75\approx140\ kg\cdot\frac{m}{s}$

Answer:

$140\ kg\cdot\frac{m}{s}$ (corresponding to the second option)