Question

1. using the periodic table, predict which compound is ionic: (1pts) \\(\square\\) \\(\ce{ch4}\\) \\(\square\\) \\(\ce{h2so4}\\) \\(\square\\) \\(\ce{rb2so4}\\) \\(\square\\) \\(\ce{c2h5oh}\\)

Explanation:

Ionic compounds form between a metal and a nonmetal (or polyatomic ion). $\text{CH}_4$ and $\text{C}_2\text{H}_5\text{OH}$ are all-nonmetal covalent compounds. $\text{H}_2\text{SO}_4$ is a covalent compound (acid) made of nonmetals. $\text{Rb}_2\text{SO}_4$ pairs rubidium (a group 1 metal) with the polyatomic sulfate ion ($\text{SO}_4^{2-}$), so it is ionic.

Answer:

$\boldsymbol{\square \ Rb_2SO_4}$ (checked option)