Question

1. $5\frac{1}{2} + 6\frac{3}{10} + \frac{4}{5}$ 27. $7\frac{1}{2} \cdot 3\frac{1}{3} \cdot \frac{4}{5} \div 5$ (30) (m) the next coordinate pair in this sequence:

Explanation:

Problem 26:

Step1: Convert to improper fractions

$5\frac{1}{2}=\frac{11}{2}$, $6\frac{3}{10}=\frac{63}{10}$, $\frac{4}{5}=\frac{4}{5}$

Step2: Find common denominator (10)

$\frac{11}{2}=\frac{55}{10}$, $\frac{4}{5}=\frac{8}{10}$

Step3: Add the fractions

$\frac{55}{10}+\frac{63}{10}+\frac{8}{10}=\frac{55+63+8}{10}=\frac{126}{10}$

Step4: Simplify the result

$\frac{126}{10}=\frac{63}{5}=12\frac{3}{5}$

Problem 27:

Step1: Convert to improper fractions

$7\frac{1}{2}=\frac{15}{2}$, $3\frac{1}{3}=\frac{10}{3}$, $5=\frac{5}{1}$

Step2: Rewrite division as multiplication

$\frac{15}{2} \times \frac{10}{3} \times \frac{4}{5} \times \frac{1}{5}$

Step3: Multiply numerators and denominators

$\frac{15 \times 10 \times 4 \times 1}{2 \times 3 \times 5 \times 5}$

Step4: Simplify step-by-step

$\frac{15}{3}=5$, $\frac{10}{2}=5$, $\frac{5}{5}=1$, leaving $\frac{5 \times 5 \times 4 \times 1}{1 \times 1 \times 1 \times 5}=\frac{100}{5}=4$

Answer:

1. $12\frac{3}{5}$ or $\frac{63}{5}$
2. $4$