Question

1. the area of the isosceles triangle is 60 square centimeters. use the equation 6h = 60 to find the height of the triangle.

the height of the triangle is 10 centimeters.
(type an integer or a simplified fraction.)

1. if the perimeter of the triangle is 38 centimeters, what is the length of each of the two sides? write an equation to solve, and let s be the side length.

Explanation:

Step1: Recall base length from prior step

From problem 26, we solve $6h=60$ to find the base is $12$ cm (since area formula $\frac{1}{2}bh=60$, so $bh=120$, and with $h=10$, $b=12$).

Step2: Set up perimeter equation

Perimeter = 2 equal sides + base: $2s + 12 = 38$

Step3: Isolate the term with $s$

Subtract 12 from both sides: $2s = 38 - 12$
$2s = 26$

Step4: Solve for $s$

Divide both sides by 2: $s = \frac{26}{2}$

Answer:

The equation is $2s + 12 = 38$, and the length of each of the two equal sides is 13 centimeters.