Question

29 randomly selected students were asked the number of movies they watched the previous week. the results are as follows: # of movies 0 1 2 3 4 5 frequency 4 8 7 6 4 0 round all your answers to 4 decimal places where possible. the mean is: 1.9310 the median is: 2 the sample standard deviation is: 1.2799 the first quartile is: 1 the third quartile is: 3 enter an integer or decimal number more... what percent of the respondents watched at least 3 movies the previous week? % 87% of all respondents watched fewer than how many movies the previous week?

Explanation:

Step1: Calculate third quartile position

$0.75 \times 29 = 21.75$

Step2: Identify Q3 value

21.75th observation in 3 movies (CF=25 ≥21.75), so Q3=3

Step3: At least 3 movies frequency

$6 + 4 + 0 = 10$

Step4: Percent for at least 3 movies

$\frac{10}{29} \times 100 \approx 34.4828$

Step5: 87% of 29 respondents

$0.87 \times 29 = 25.23$

Step6: Find movies for 87%

CF=25 (3 movies) <25.23, next CF=29 (4 movies), so 4

Answer:

3
34.4828
4