Question

2c₈h₁₈ + 25o₂ → 16co₂ + 18h₂o
the combustion reaction can theoretically produce 1.60 moles of carbon dioxide. however, only 0.95 moles are collected.
what is the percent yield of the reaction?
? %

Explanation:

Step1: Recall percent yield formula

The formula for percent yield is $\text{Percent Yield} = \frac{\text{Actual Yield}}{\text{Theoretical Yield}} \times 100\%$.

Step2: Identify actual and theoretical yields

Actual yield is 0.95 moles (collected), theoretical yield is 1.60 moles (theoretical).

Step3: Plug values into formula

$\text{Percent Yield} = \frac{0.95}{1.60} \times 100\%$. Calculate $\frac{0.95}{1.60} = 0.59375$, then multiply by 100%: $0.59375 \times 100\% = 59.375\%$.

Answer:

59.375 (or rounded as needed, e.g., 59.4)