Question

2h₂ + 1o₂ →→ 2h₂o if you change the 2h₂ to 3h₂ molecules and balance the equation, identify which statement is correct? (1 point) the equation will produce three molecules of water. each oxygen molecule will combine with 2 hydrogen molecules with no leftover molecules. it is not possible to produce water without leftover molecules. the result of the equation will be the same.

Explanation:

Step1: Write the new un - balanced equation

The original equation is $2H_2 + O_2
ightarrow2H_2O$. When we change $2H_2$ to $3H_2$, the un - balanced equation is $3H_2+O_2
ightarrow H_2O$.

Step2: Balance the equation

To balance the hydrogen atoms, if we have 3 moles of $H_2$, we can produce 3 moles of $H_2O$. The equation becomes $3H_2 + \frac{3}{2}O_2
ightarrow3H_2O$. Since we can't have a fraction of a molecule in a chemical equation in the context of whole - number coefficients for molecules in a reaction, we multiply through by 2 to get $6H_2+3O_2
ightarrow6H_2O$. But considering the non - multiplied form with 3 moles of $H_2$, we know that hydrogen and oxygen do not combine in a 1:1 ratio to form water. For every 2 moles of hydrogen, we need 1 mole of oxygen. With 3 moles of hydrogen, we need 1.5 moles of oxygen. So, it is not possible to produce water without leftover molecules.

Answer:

It is not possible to produce water without leftover molecules.