Question

2naoh + h₂so₄ → 2h₂o + na₂so₄
50.0 ml of 0.50 m h₂so₄ is added to
60.0 ml of 0.80 m naoh. the resulting
temperature change is an increase of
1.20 °c.

c_sol = 4.20 j/g °c d_sol = 1.05 g/ml c_cal = 4.50 j/°c

what is the mass of the solution?
mass_sol = ? g

Explanation:

Step1: Find total volume of solution

The volume of \(H_2SO_4\) is \(50.0\) mL and the volume of \(NaOH\) is \(60.0\) mL. So total volume \(V = 50.0 + 60.0 = 110.0\) mL.

Step2: Calculate mass using density formula

Density formula is \(d=\frac{m}{V}\), so \(m = d\times V\). Given \(d_{sol}=1.05\) g/mL and \(V = 110.0\) mL. Then \(m = 1.05\times110.0\).

Answer:

\(115.5\)