Question

2x - 8
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factor the expression.
14y^4 - 12y^3 - 16y^2
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(3y^2)(42y^2 - 6y - 8) (2y^2)(42y^2 - 6y - 8)
(2y^2)(7y^2 - 6y - 16) (2y^2)(7y^2 - 6y - 8)

Explanation:

Step1: Factor out GCF of first - expression

Find the GCF of \(2x\) and \(8\). The GCF of \(2\) and \(8\) is \(2\). So, \(2x - 8=2(x - 4)\).

Step2: Factor out GCF of second - expression

For \(14y^{4}-12y^{3}-16y^{2}\), the GCF of \(14\), \(12\) and \(16\) is \(2\), and the GCF of \(y^{4}\), \(y^{3}\) and \(y^{2}\) is \(y^{2}\).
\[

$$\begin{align*} 14y^{4}-12y^{3}-16y^{2}&=2y^{2}(7y^{2}-6y - 8) \end{align*}$$

\]

Answer:

For \(2x - 8\): \(2(x - 4)\)
For \(14y^{4}-12y^{3}-16y^{2}\): \((2y^{2})(7y^{2}-6y - 8)\)