Question

for 3-10, subtract the fractions.

1. $\frac{2}{3} - \frac{1}{3}$
2. $\frac{3}{4} - \frac{2}{4}$
3. $\frac{5}{6} - \frac{2}{6}$
4. $\frac{9}{12} - \frac{3}{12}$
5. $\frac{9}{8} - \frac{3}{8}$
6. $\frac{17}{10} - \frac{9}{10}$
7. $\frac{4}{8} - \frac{1}{8}$
8. $\frac{1}{2} - \frac{1}{2}$

Explanation:

Problem 3: $\boldsymbol{\frac{2}{3} - \frac{1}{3}}$

Step1: Subtract numerators (same denominator)

For fractions with the same denominator, we subtract the numerators and keep the denominator. So, $\frac{2 - 1}{3}$.

Step2: Simplify the numerator

$2 - 1 = 1$, so the result is $\frac{1}{3}$.

Step1: Subtract numerators (same denominator)

Using the rule for subtracting fractions with the same denominator: $\frac{3 - 2}{4}$.

Step2: Simplify the numerator

$3 - 2 = 1$, so we get $\frac{1}{4}$.

Step1: Subtract numerators (same denominator)

Apply the fraction subtraction rule: $\frac{5 - 2}{6}$.

Step2: Simplify the numerator

$5 - 2 = 3$, so the fraction becomes $\frac{3}{6}$, which simplifies to $\frac{1}{2}$ (by dividing numerator and denominator by 3).

Answer:

$\frac{1}{3}$

Problem 4: $\boldsymbol{\frac{3}{4} - \frac{2}{4}}$