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Question
if n(-3,1) is reflected across the line y = -2, then n is (-1,1).
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Step1: Calculate vertical distance
The vertical distance between $y = 1$ (y - coordinate of $N(-3,1)$) and $y=-2$ is $d=1-(-2)=3$.
Step2: Find new y - coordinate
When reflecting across $y = - 2$, the new y - coordinate of the reflected point $N'$ is $-2-(3)=-5$ (since we go the same distance below the line $y = - 2$). The x - coordinate remains the same, so $N'$ is $(-3,-5)$.
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False