Question

3ba(no₃)₂ + 2na₃po₄ → ba₃(po₄)₂ + 6nano₃
the reaction is initiated with 21.0 g ba(no₃)₂ and 10.0 g na₃po₄. the reaction uses up all the ba(no₃)₂ and 8.78 g na₃po₄. what mass of na₃po₄ remains after the reaction is complete?
? g na₃po₄

Explanation:

Step1: Identify initial and used mass of Na₃PO₄

Initial mass of \( \text{Na}_3\text{PO}_4 \) is \( 10.0 \, \text{g} \), and the mass used is \( 8.78 \, \text{g} \).

Step2: Calculate remaining mass

To find the remaining mass, subtract the mass used from the initial mass. The formula is: \( \text{Remaining mass} = \text{Initial mass} - \text{Mass used} \)
Substituting the values: \( 10.0 - 8.78 = 1.22 \)

Answer:

\( 1.22 \)