Question

0.400 m albr3
express your answer with the appropriate units.
br^- = value units

Explanation:

Step1: Write dissociation equation

$AlBr_3(s)
ightarrow Al^{3 +}(aq)+3Br^{-}(aq)$

Step2: Determine bromide - ion concentration

From the equation, 1 mole of $AlBr_3$ produces 3 moles of $Br^{-}$. Given $[AlBr_3]=0.400\ M$, then $[Br^{-}]=3\times[AlBr_3]$.
$[Br^{-}]=3\times0.400\ M$

Answer:

$1.20\ M$