Question

75 gumballs are in a bag. 18 of them are green. what is the probability of drawing 2 green gumballs if the first one is placed back in the bag before the second draw? round your answer to the nearest hundredth.

Explanation:

Step1: Calculate probability of first draw

The probability of drawing a green gumball on the first draw is the number of green gumballs divided by the total number of gumballs. So the probability $P_1=\frac{18}{75} = 0.24$.

Step2: Calculate probability of second draw

Since the first gumball is replaced, the probability of drawing a green gumball on the second draw is also $P_2=\frac{18}{75}= 0.24$.

Step3: Calculate probability of both events

Since the two draws are independent events, the probability of both drawing green gumballs is the product of the probabilities of each draw. So $P = P_1\times P_2=0.24\times0.24 = 0.0576\approx0.06$.

Answer:

0.06