Question

75 gumballs are in a bag. 18 of them are green. what is the probability of drawing 2 green gumballs if the first one is placed back in the bag before the second draw? round your answer to the nearest hundredth.

Explanation:

Step1: Calculate probability of first - draw

The probability of drawing a green gumball on the first draw is the number of green gumballs divided by the total number of gumballs. So, $P_1=\frac{18}{75}= 0.24$.

Step2: Calculate probability of second - draw

Since the first gumball is replaced, the probability of drawing a green gumball on the second draw is the same as the first draw, $P_2=\frac{18}{75}=0.24$.

Step3: Calculate probability of both events

For independent events (drawing with replacement), the probability of both events occurring is the product of their individual probabilities. So, $P = P_1\times P_2=0.24\times0.24 = 0.0576$.

Step4: Round the answer

Rounding 0.0576 to the nearest hundredth gives 0.06.

Answer:

0.06