Question

(k²+7k-24)÷(k+10)
-2, r11
k-3, r 6
-4, r 9
-1, r 4

Explanation:

Step1: Factor the numerator

$k^2+7k-24=(k+10)(k-3)+6$

Step2: Perform polynomial division

$\frac{k^2+7k-24}{k+10}=\frac{(k+10)(k-3)+6}{k+10}=k-3+\frac{6}{k+10}$

Step3: Identify quotient and remainder

Quotient: $k-3$, Remainder: $6$

Answer:

k-3, R 6