Question

1. what is the mass of a cube of aluminum that is 3.0 cm on each edge? the density of aluminum is 2.7 g/cm³.

Explanation:

Step1: Calculate volume of cube

The volume formula for a cube is $V = s^3$, where $s$ is the side - length. Given $s = 3.0\ cm$, so $V=(3.0\ cm)^3 = 27\ cm^3$.

Step2: Calculate mass using density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. Rearranging for mass gives $m=
ho V$. Given $
ho = 2.7\ g/cm^3$ and $V = 27\ cm^3$, then $m=(2.7\ g/cm^3)\times(27\ cm^3)=72.9\ g$.

Answer:

$72.9\ g$