Question

is △abc≅△dfe by aas theorem? (1 point) yes. the aas theorem is used no (overline{de}) does not correspond to (overline{bc}) no. the asa theorem is used yes (overline{bc}congoverline{fe})

Explanation:

Step1: Recall AAS theorem

The AAS (Angle - Angle - Side) theorem states that if two angles and a non - included side of one triangle are congruent to two angles and the corresponding non - included side of another triangle, then the two triangles are congruent.

Step2: Analyze the given triangles

In \(\triangle ABC\) and \(\triangle DFE\), we have two pairs of angles marked as congruent. But for AAS, the congruent sides must be non - included between the two pairs of congruent angles. Here, the congruent sides are not the non - included sides for the given pairs of congruent angles. Also, the AAS theorem requires the non - included sides to be corresponding. The side \(BC\) in \(\triangle ABC\) and \(DE\) in \(\triangle DFE\) are not corresponding sides for the pairs of congruent angles. In fact, for these triangles, the congruence criterion used (if applicable) would be ASA (Angle - Side - Angle) since the congruent side is included between the two pairs of congruent angles.

Answer:

No. The ASA Theorem is used.