QUESTION IMAGE
Question
ac and db are chords that intersect at point h. what is the length of line segment db? 4 units 8 units 16 units 20 units
Response
- Recall the intersecting - chords theorem:
- The intersecting - chords theorem states that if two chords \(AC\) and \(DB\) intersect at a point \(H\) inside a circle, then \(AH\times HC=DH\times HB\).
- Given \(AH = 20 - x\), \(HC=x\), \(DH=x + 4\), and \(HB=12 - x\).
- So, \((20 - x)\times x=(x + 4)\times(12 - x)\).
- Expand both sides:
- The left - hand side is \(20x-x^{2}\), and the right - hand side is \(12x-x^{2}+48 - 4x=8x - x^{2}+48\).
- Set them equal: \(20x-x^{2}=8x - x^{2}+48\).
- Subtract \(-x^{2}\) from both sides of the equation, we get \(20x=8x + 48\).
- Subtract \(8x\) from both sides: \(20x-8x=48\), which simplifies to \(12x = 48\).
- Solve for \(x\): \(x = 4\).
- Calculate the length of \(DB\):
- Since \(DB=DH + HB\), and \(DH=x + 4\), \(HB=12 - x\).
- Substitute \(x = 4\) into the expressions for \(DH\) and \(HB\).
- \(DH=4 + 4=8\) and \(HB=12 - 4 = 8\).
- Then \(DB=8 + 8=16\) units.
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16 units