Question

add two symbols and two numbers.
110 c 110
ag → a + b
47 d 48
a = 1
b = 2
c = 3
d = 4
the type of nuclear reaction is 5 and it emits 6 radiation.
the reaction is not bombardment and so it is 7 and the half - life concept applies.
a. 0 b. 1 c. -1 d. 2 e. 3 f. 4 g. 5 h. 6
i. radiation j. fusion k. none l. fission m. spontaneous
n. electron capture o. bombardment p. α (alpha) q. β (beta)

Explanation:

Step1: Analyze nuclear - reaction mass - number and atomic - number conservation

For a nuclear reaction of silver ($_{47}^{110}Ag$) decaying into two products $A$ and $B$. In a radioactive decay, the sum of mass - numbers and atomic - numbers on both sides of the equation must be equal.

Step2: Determine the products

If we assume a beta - decay ($_{47}^{110}Ag
ightarrow_{48}^{110}X + _{ - 1}^{0}e$), where $X$ is a daughter nucleus and $e$ is an electron.

1. For the electron (beta particle), its mass - number is 0 and atomic - number is - 1. So $A$ (the electron) has mass - number 0 and atomic - number - 1. So $A$ corresponds to option C (-1).
2. The daughter nucleus has atomic number 48 and mass number 110. The change in atomic number from 47 to 48 indicates a beta - decay. The daughter nucleus has a mass - number of 110 and atomic - number of 48. So $B$ corresponds to option A (0).
3. In nuclear reactions, the symbol for mass - number is $A$ and for atomic number is $Z$. Here, the mass - number of silver is 110. So $C$ corresponds to the symbol for mass - number which is not given in the options in a proper context. But if we consider the general nuclear - notation, the first number near the element symbol is mass - number. So we assume $C$ is the mass - number symbol, but among the given options, if we consider the nature of the problem related to nuclear decay values, it has no relevant option. Let's assume it is a mis - written part. If we consider the numbers in the context of decay values, the most relevant is the atomic - number change. In beta - decay, the change in atomic number is due to the emission of an electron. The electron has an atomic number of - 1. So if we assume $C$ is related to the change in atomic number in decay, $C$ corresponds to option C (-1).
4. The atomic number of silver is 47 and the daughter nucleus has atomic number 48. The change in atomic number is 1. So $D$ corresponds to option B (1).
5. Since it is a decay of a single nucleus into two products and not a combination (fusion) or splitting due to bombardment, and it is a beta - decay, the type of nuclear reaction is a decay. Among the given options, the closest is electron capture (although beta - decay is also a type of radioactive decay and electron capture is related in terms of charge - changing decay processes). But if we consider the options strictly, the best fit is electron capture (N).
6. In this case of beta - decay, the emitted radiation is beta radiation. So it corresponds to option Q ($\beta$ (beta)).
7. Since the reaction is not bombardment, it is a spontaneous process as it occurs naturally without external particle bombardment. So it corresponds to option M (spontaneous).

Answer:

1. C. -1
2. A. 0
3. C. -1
4. B. 1
5. N. electron capture
6. Q. $\beta$ (beta)
7. M. spontaneous