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adult men have heights with a mean of 69.0 inches and a standard deviat…

Question

adult men have heights with a mean of 69.0 inches and a standard deviation of 2.8 inches. find the z - score of a man who is 78.5 inches tall. (round answer to 2 decimal places)

Explanation:

Step1: Recall z - score formula

The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $x$ is the value, $\mu$ is the mean, and $\sigma$ is the standard deviation.

Step2: Identify values

Here, $x = 78.5$, $\mu=69.0$, and $\sigma = 2.8$.

Step3: Substitute values into formula

$z=\frac{78.5 - 69.0}{2.8}=\frac{9.5}{2.8}\approx3.39$

Answer:

$3.39$