QUESTION IMAGE
Question
the ages and masses of vehicles of drivers who received speeding tickets in the past 30 days is shown in the table below. use this information to answer parts a through c.
| age groups | under 1500 kg | over 1500 kg |
|---|---|---|
| 26 - 35 | 190 | 173 |
| 36 - 45 | 154 | 190 |
| 46 - 55 | 80 | 82 |
| >= 56 | 124 | 181 |
(round to three decimal places as needed.)
| age group | relative frequency |
|---|---|
| 26-35 | 0.233 |
| 36-45 | 0.188 |
| 46-55 | 0.098 |
| >= 56 | 0.162 |
(b) construct a relative frequency distribution of the drivers with vehicles over 1500 kg who received tickets.
(round to three decimal places as needed.)
| age group | relative frequency |
|---|---|
| 26-35 | |
| 36-45 | |
| 46-55 | |
| >= 56 |
Step1: Calculate total number of drivers with vehicles over 1500 kg
First, we sum up the frequencies for "over 1500 kg" across all age groups.
The frequencies are 224 (16 - 25), 173 (26 - 35), 160 (36 - 45), 82 (46 - 55), and 161 (≥ 56).
So total \( N = 224 + 173 + 160 + 82 + 161 \)
\( N = 224 + 173 = 397 \); \( 397 + 160 = 557 \); \( 557 + 82 = 639 \); \( 639 + 161 = 800 \)
Step2: Calculate relative frequency for each age group
For 16 - 25:
Relative Frequency \( = \frac{224}{800} = 0.280 \)
For 26 - 35:
Relative Frequency \( = \frac{173}{800} = 0.21625 \approx 0.216 \) (rounded to three decimal places)
For 36 - 45:
Relative Frequency \( = \frac{160}{800} = 0.200 \)
For 46 - 55:
Relative Frequency \( = \frac{82}{800} = 0.1025 \approx 0.103 \) (rounded to three decimal places)
For ≥ 56:
Relative Frequency \( = \frac{161}{800} = 0.20125 \approx 0.201 \) (rounded to three decimal places)
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| Age Group | Relative Frequency |
|---|---|
| 26 - 35 | 0.216 |
| 36 - 45 | 0.200 |
| 46 - 55 | 0.103 |
| ≥ 56 | 0.201 |