Question

algebra 1-23511200310d101
6-3: mathxl for school: additional practice
multiply, using special product methods.
$6 + (3b + 2)^2$
$6 + (3b + 2)^2 = \square$ (simplify your answer.)

Explanation:

Step1: Combine like terms inside brackets

$[6 + (3b + 2)]^2 = (3b + 8)^2$

Step2: Apply square of sum formula

Recall the special product: $(a+b)^2 = a^2 + 2ab + b^2$, where $a=3b$, $b=8$.

$$\begin{align*} (3b + 8)^2 &= (3b)^2 + 2(3b)(8) + 8^2 \end{align*}$$

Step3: Calculate each term

$$\begin{align*} (3b)^2 + 2(3b)(8) + 8^2 &= 9b^2 + 48b + 64 \end{align*}$$

Answer:

$9b^2 + 48b + 64$