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algebraic inequalities - ho 1) 2x + 1 > 9

Question

algebraic inequalities - ho

  1. 2x + 1 > 9

Explanation:

Step1: Subtract 1 from both sides

To isolate the term with \( x \), we subtract 1 from both sides of the inequality \( 2x + 1>9 \). This gives us \( 2x+1 - 1>9 - 1 \), which simplifies to \( 2x>8 \).

Step2: Divide both sides by 2

To solve for \( x \), we divide both sides of the inequality \( 2x > 8 \) by 2. So, \( \frac{2x}{2}>\frac{8}{2} \), which simplifies to \( x > 4 \).

Answer:

\( x > 4 \)