Question

all radicals.
$-17 + \sqrt{-11}$
submit
work it out
not feeling ready yet? this can help:

Explanation:

Step1: Rewrite negative radical

Recall that $\sqrt{-a} = i\sqrt{a}$ for $a>0$. So $\sqrt{-11} = i\sqrt{11}$.

Step2: Combine with constant term

Substitute back into the original expression.
$-17 + i\sqrt{11}$

Answer:

$-17 + i\sqrt{11}$