Question

aluminum and copper(i) chloride undergoes a single replacement reaction. predict the formulae of the two products of the reaction. tap to select or deselect answer. cu and alcl₂ al₂cu₃ and cl cu and alcl al₂cu₃ and cl₂ cu and alcl₃

Explanation:

In a single - replacement reaction, a more reactive metal replaces a less reactive metal in a compound. Aluminum (Al) is more reactive than copper (Cu). The reaction between aluminum (Al) and copper(I) chloride ($CuCl$) follows the pattern: $2Al + 3CuCl
ightarrow3Cu + 2AlCl_{3}$. Let's analyze each option:

• Option 1: The formula for aluminum chloride is incorrect. Aluminum has a + 3 oxidation state and chlorine has a - 1 oxidation state, so the correct formula should be $AlCl_{3}$, not $AlCl_{2}$.
• Option 2: This is not the correct product of a single - replacement reaction between Al and $CuCl$. The reaction is a single - replacement, not a reaction that would form $Al_{2}Cu_{3}$ and $Cl$.
• Option 3: The formula for aluminum chloride is incorrect. As mentioned, it should be $AlCl_{3}$.
• Option 4: This is not the correct product of the single - replacement reaction. The reaction will produce elemental copper and aluminum chloride, not $Al_{2}Cu_{3}$ and $Cl_{2}$.
• Option 5: The reaction between Al and $CuCl$ (copper(I) chloride) will produce copper (Cu) and aluminum chloride ($AlCl_{3}$) according to the single - replacement reaction principles.

Answer:

E. Cu and $AlCl_{3}$