Question

an amusement park reports that the probability of a visitor riding its largest roller coaster is 30 percent, the probability of a visitor riding its smallest roller coaster is 20 percent, and the probability of a visitor riding both roller coasters is 15 percent. which equation can be used to calculate the probability of a visitor riding the largest or the smallest roller coaster? p(largest or smallest) = 0.30 - 0.20 p(largest or smallest) = 0.30 + 0.15 - 0.20 p(largest or smallest) = 0.30 + 0.20 - 0.15 p(largest or smallest) = 0.30 + 0.20

Explanation:

Step1: Recall probability formula

The formula for the probability of the union of two events $A$ and $B$ is $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. Let event $A$ be riding the largest roller - coaster and event $B$ be riding the smallest roller - coaster.

Step2: Identify given probabilities

We are given that $P(A) = 0.30$ (probability of riding the largest roller - coaster), $P(B)=0.20$ (probability of riding the smallest roller - coaster), and $P(A\cap B) = 0.15$ (probability of riding both).

Step3: Substitute values into formula

Substituting the values into the formula $P(A\cup B)=P(A)+P(B)-P(A\cap B)$, we get $P(\text{largest or smallest})=0.30 + 0.20-0.15$.

Answer:

$P(\text{largest or smallest}) = 0.30 + 0.20-0.15$