Question

anders throws a baseball straight up from a height of 3 feet above the ground. the initial velocity of the baseball is 25 feet per second. what is the height of the ball 1.5 seconds after it is thrown? round your answer to the nearest hundredth. (1 point)

Explanation:

Step1: Identify the kinematic - height formula

The formula for the height $h(t)$ of an object in vertical - motion under the influence of gravity is $h(t)=h_0 + v_0t-\frac{1}{2}gt^2$, where $h_0$ is the initial height, $v_0$ is the initial velocity, $t$ is the time, and $g$ is the acceleration due to gravity. In English units, $g = 32$ ft/s², $h_0 = 3$ feet, $v_0=25$ ft/s, and $t = 1.5$ s.

Step2: Substitute the values into the formula

$h(1.5)=3+25\times1.5-\frac{1}{2}\times32\times(1.5)^2$.
First, calculate each term:
$25\times1.5 = 37.5$.
$\frac{1}{2}\times32\times(1.5)^2=16\times2.25 = 36$.

Step3: Calculate the height

$h(1.5)=3 + 37.5-36$.
$h(1.5)=40.5 - 36$.
$h(1.5)=4.50$ feet.

Answer:

$4.50$ feet