QUESTION IMAGE
Question
angle relationships
- find m∠dce.
- find m∠hki.
- find the value of x.
4)
∠deg = 85°
∠gef =
∠def = 142°
Step1: Find \(m\angle DCE\) in the first - figure
The sum of angles around a point is \(360^{\circ}\). In the first figure, if we assume the right - angle is \(90^{\circ}\), then \(m\angle DCE=360^{\circ}-90^{\circ}-67^{\circ}=203^{\circ}\).
Step2: Find \(m\angle HKI\) in the second - figure
The sum of angles around a point is \(360^{\circ}\). So \(m\angle HKI = 360^{\circ}-127^{\circ}-151^{\circ}=82^{\circ}\).
Step3: Find the value of \(x\) in the third - figure
The sum of angles around a point is \(360^{\circ}\), and we have two right - angles (\(90^{\circ}\) each). So \((3x - 1)+4x+90 + 90=360\). Combine like terms: \(7x+180 = 360\). Subtract 180 from both sides: \(7x=360 - 180=180\). Then \(x=\frac{180}{7}\approx25.71\).
Step4: Find \(\angle GEF\) in the fourth - figure
We know that \(\angle DEF = 142^{\circ}\) and \(\angle DEG = 85^{\circ}\). Then \(\angle GEF=\angle DEF-\angle DEG=142^{\circ}-85^{\circ}=57^{\circ}\).
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- \(m\angle DCE = 203^{\circ}\)
- \(m\angle HKI = 82^{\circ}\)
- \(x=\frac{180}{7}\)
- \(\angle GEF = 57^{\circ}\)