Question

your answer is incorrect.
factor.
$64 - 27w^3$

Explanation:

Step1: Identify difference of cubes

$64 = 4^3$, $27w^3=(3w)^3$, so $64-27w^3=4^3-(3w)^3$

Step2: Apply difference of cubes formula

Use $a^3-b^3=(a-b)(a^2+ab+b^2)$, let $a=4$, $b=3w$

$$\begin{align*} 4^3-(3w)^3&=(4-3w)(4^2 + 4\cdot3w + (3w)^2)\\ &=(4-3w)(12w + 9w^2 + 16) \end{align*}$$

Step3: Rearrange terms (optional, standard order)

$(4-3w)(9w^2+12w+16)$

Answer:

$(4-3w)(9w^2 + 12w + 16)$