Question

applying the acute triangle inequality theorem. use the drop - down menus to complete the statements. 4² is 3² + 3². therefore, △jkl is. 5² is 3² + 4². applying the same method, △abc is. acute right neither acute nor right

Explanation:

Step1: Calculate the squares

$4^{2}=16$, $3^{2}+3^{2}=9 + 9=18$. Since $16<18$, so $4^{2}<3^{2}+3^{2}$.

Step2: Determine the type of $\triangle{JKL}$

For a triangle with side - lengths $a$, $b$, $c$ (where $c$ is the longest side), if $c^{2}

Step3: Calculate for $\triangle{ABC}$

$5^{2}=25$, $3^{2}+4^{2}=9 + 16=25$. Since $5^{2}=3^{2}+4^{2}$, by the Pythagorean theorem, $\triangle{ABC}$ is right.

Answer:

$4^{2}$ is $<$ $3^{2}+3^{2}$. Therefore, $\triangle{JKL}$ is acute. $5^{2}$ is $=$ $3^{2}+4^{2}$. Applying the same method, $\triangle{ABC}$ is right.