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Question
applying the cosine law
example 2 a nebo svu counter - stealth radar has detected an f - 35 fighter jet at a range of 41 km and is tracking an su - 35s russian fighter jet at 34 km. the angle between the two aircraft is 112°. how far apart are they rounded to nearest tenth?
answer solution
Step1: Recall the cosine - law formula
The cosine - law for a triangle with sides \(a\), \(b\), \(c\) and the angle \(C\) between sides \(a\) and \(b\) is \(c^{2}=a^{2}+b^{2}-2ab\cos C\). Let \(a = 41\), \(b = 34\), and \(C=112^{\circ}\).
Step2: Substitute values into the formula
\[
$$\begin{align*}
c^{2}&=41^{2}+34^{2}-2\times41\times34\times\cos(112^{\circ})\\
c^{2}&=1681 + 1156-2788\times(- 0.3746)\\
c^{2}&=1681+1156 + 1044.4848\\
c^{2}&=3881.4848
\end{align*}$$
\]
Step3: Find the value of \(c\)
\[c=\sqrt{3881.4848}\approx62.3\]
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\(62.3\) km