Question

archie is fed up with waiting in line at his local post office, and plans to contact his congresswoman. archie knows that his complaint will not be well received without data to back it up. so to improve his case, over the next few months archie records the waiting time for a selection of 26 post office visits made by him and other customers. these waiting times (in minutes) are summarized in the following frequency distribution. waiting time (in minutes) frequency 0 to 6 2 7 to 13 9 14 to 20 7 21 to 27 6 28 to 34 2 based on the frequency distribution, using the midpoint of each data class, estimate the mean waiting time for the data archie collected. for your intermediate computations, use four or more decimal places.

Explanation:

Step1: Find mid - points of each class

For 0 - 6, mid - point $x_1=\frac{0 + 6}{2}=3$; for 7 - 13, mid - point $x_2=\frac{7+13}{2}=10$; for 14 - 20, mid - point $x_3=\frac{14 + 20}{2}=17$; for 21 - 27, mid - point $x_4=\frac{21+27}{2}=24$; for 28 - 34, mid - point $x_5=\frac{28 + 34}{2}=31$.

Step2: Calculate the product of mid - point and frequency for each class

$x_1f_1=3\times2 = 6$; $x_2f_2=10\times9 = 90$; $x_3f_3=17\times7 = 119$; $x_4f_4=24\times6 = 144$; $x_5f_5=31\times2=62$.

Step3: Find the sum of the products and the sum of the frequencies

$\sum_{i = 1}^{5}x_if_i=6 + 90+119+144+62=421$; $\sum_{i = 1}^{5}f_i=2 + 9+7+6+2=26$.

Step4: Calculate the mean

The mean $\bar{x}=\frac{\sum_{i = 1}^{5}x_if_i}{\sum_{i = 1}^{5}f_i}=\frac{421}{26}\approx16.1923$.

Answer:

$16.1923$