Question

ardem collected data from a class survey. he then randomly selected samples of five responses to generate four samples.

survey data
sample 1 | 4 | 5 | 2 | 4 | 3
sample 2 | 2 | 2 | 6 | 5 | 7
sample 3 | 4 | 6 | 3 | 4 | 1
sample 4 | 5 | 2 | 4 | 3 | 6

using his four samples, between what two numbers will ardem’s actual population mean lie?
○ 1 and 6
○ 2 and 5
○ 3.6 and 4.4
○ 4.0 and 4.4

Explanation:

Step1: Calculate Sample 1 mean

$\text{Mean}_1 = \frac{4+5+2+4+3}{5} = \frac{18}{5} = 3.6$

Step2: Calculate Sample 2 mean

$\text{Mean}_2 = \frac{2+2+6+5+7}{5} = \frac{22}{5} = 4.4$

Step3: Calculate Sample 3 mean

$\text{Mean}_3 = \frac{4+6+3+4+1}{5} = \frac{18}{5} = 3.6$

Step4: Calculate Sample 4 mean

$\text{Mean}_4 = \frac{5+2+4+3+6}{5} = \frac{20}{5} = 4.0$

Step5: Find min and max sample means

Minimum sample mean = 3.6, Maximum sample mean = 4.4

Answer:

3.6 and 4.4