QUESTION IMAGE
Question
- the area of a triangle must be greater than $24\\ in^{2}$
$\frac{1}{2}bh > 24$
solve the inequality for $h$ if the base, $b$, is 8 inches.
(write the simplified algebraic inequality.)
Step1: Substitute b=8 into inequality
$\frac{1}{2}(8)h > 24$
Step2: Simplify left-hand side
$4h > 24$
Step3: Isolate h by dividing by 4
$h > \frac{24}{4}$
Step4: Compute the right-hand side
$h > 6$
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$h > 6$