Question

arrange the fertilizers in decreasing order of mass percentage of nitrogen. highest percent nitrogen lowest percent nitrogen answer bank (nh₄)₂so₄ nh₃ kno₃ (nh₄)₂hpo₄ (nh₄)h₂po₄ nh₄no₃

Explanation:

Step1: Calculate molar mass of each compound

Molar mass of $(NH_4)_2SO_4$: $2\times(14 + 4\times1)+32+4\times16=132\ g/mol$, mass - percentage of $N$: $\frac{2\times14}{132}\times100\%\approx21.2\%$
Molar mass of $NH_3$: $14 + 3\times1 = 17\ g/mol$, mass - percentage of $N$: $\frac{14}{17}\times100\%\approx82.4\%$
Molar mass of $KNO_3$: $39+14 + 3\times16=101\ g/mol$, mass - percentage of $N$: $\frac{14}{101}\times100\%\approx13.9\%$
Molar mass of $(NH_4)_2HPO_4$: $2\times(14 + 4\times1)+1+31+4\times16 = 132\ g/mol$, mass - percentage of $N$: $\frac{2\times14}{132}\times100\%\approx21.2\%$
Molar mass of $(NH_4)H_2PO_4$: $14+4\times1 + 2\times1+31+4\times16 = 115\ g/mol$, mass - percentage of $N$: $\frac{14}{115}\times100\%\approx12.2\%$
Molar mass of $NH_4NO_3$: $2\times14+4\times1+3\times16 = 80\ g/mol$, mass - percentage of $N$: $\frac{2\times14}{80}\times100\% = 35\%$

Step2: Arrange in decreasing order

$NH_3>NH_4NO_3>(NH_4)_2SO_4=(NH_4)_2HPO_4>KNO_3>(NH_4)H_2PO_4$

Answer:

$NH_3,NH_4NO_3,(NH_4)_2SO_4,(NH_4)_2HPO_4,KNO_3,(NH_4)H_2PO_4$