Question

1. the arrow on each spinner is spun once. if each spinner has equal-sized sections, what is the probability of selecting a b on the first spinner and a z on the second spinner?$\frac{1}{20}$$\frac{1}{12}$$\frac{1}{6}$$\frac{1}{4}$

Explanation:

Step1: Find P(B) on first spinner

First spinner has 4 equal sections. Probability of B: $\frac{1}{4}$

Step2: Find P(Y) on second spinner

Second spinner has 3 equal sections. Probability of Y: $\frac{1}{3}$

Step3: Calculate combined probability

Multiply the two independent probabilities: $\frac{1}{4} \times \frac{1}{3}$

Answer:

$\frac{1}{12}$ (corresponding to the second option: $\boldsymbol{\frac{1}{12}}$)