Question

1. an atom of an element \a\ have equal percentage of isotopes, a - 50 amu and a - 52 amu. what would be average atomic mass of the atom?

o 50 amu
o 50.5 amu
o 51 amu
o 52 amu

Explanation:

Step1: Recall average - atomic - mass formula

The formula for the average atomic mass of an element with two isotopes is $A = x_1m_1 + x_2m_2$, where $x_1$ and $x_2$ are the fractional abundances of the isotopes and $m_1$ and $m_2$ are their masses. Since the percentages are equal, $x_1=x_2 = 0.5$.

Step2: Substitute values into formula

Let $m_1 = 50$ amu and $m_2=52$ amu. Then $A=(0.5\times50)+(0.5\times52)$.

Step3: Calculate the result

$A = 25 + 26=51$ amu.

Answer:

51 amu