Question

atomic structure worksheet
date:
① identify the each of the parts of the box and fill in the blank.
8
oxygen
15.999
atomic number =
atomic mass =

of protons =

of electrons =

of neutrons =

② how many protons and neutrons are present is an atom of titanium (mass number = 48)?
protons =
neutrons =
③ what is the mass number, symbol, and charge of an ion that contains 87 protons, 136 neutrons, and 86 electrons?
mass number =
symbol =
charge =
④ write the complete name and chemical symbol for the ion with 37 protons, 48 neutrons, and 36 electrons.
⑤ how many protons, neutrons, and electrons are present in the ^(93)nb^(3 +) ion?
protons =
electrons =
neutrons =
⑥ how many protons, neutrons, and electrons are present in the ^(140)ce^(4 +) ion?
protons =
electrons =
neutrons =
⑦ an atom with an atomic number of 7 and a mass number of 14 is which element?
(a) h
(b) n
(c) o
(d) p
⑧ usually, the atom described in problem 7 will have how many electrons?
(a) 4
(b) 7
(c) 8
(d) 15
⑨ a neutral atom of copper has how many electrons?
(a) 15
(b) 18
(c) 26
(d) 29
⑩ what is the atomic mass in amu of an atom that has 14 protons, 14 electrons, and 14 neutrons?
(a) 14
(b) 28
(c) 42
(d) 56

Explanation:

Step1: Recall atomic structure concepts

Atomic number = number of protons. Atomic mass ≈ number of protons + number of neutrons. In a neutral atom, number of protons = number of electrons. For ions, adjust electron count based on charge.

Step2: Answer question 1

For oxygen: Atomic number = 8, Atomic mass = 15.999, # of protons = 8, # of electrons (in neutral atom) = 8, # of neutrons = 15.999 - 8 ≈ 8 (rounded).

Step3: Answer question 2

Titanium has atomic number 22. Protons = 22. Mass number = 48, Neutrons = 48 - 22 = 26.

Step4: Answer question 3

Protons = 87, Neutrons = 136, Mass number = 87+136 = 223. Symbol is Fr (francium). Charge = 87 - 86 = + 1.

Step5: Answer question 4

Protons = 37, Neutrons = 48, Electrons = 36. Element is Rb (rubidium). Symbol is $Rb^{+}$. Name is rubidium ion.

Step6: Answer question 5

For $^{93}Nb^{3 +}$: Protons = 41, Electrons = 41 - 3 = 38, Neutrons = 93 - 41 = 52.

Step7: Answer question 6

For $^{140}Ce^{4+}$: Protons = 58, Electrons = 58 - 4 = 54, Neutrons = 140 - 58 = 82.

Step8: Answer question 7

Atomic number 7 is nitrogen (N).

Step9: Answer question 8

Nitrogen (atomic number 7) has 7 electrons in neutral state.

Step10: Answer question 9

Copper (Cu) has atomic number 29, a neutral atom has 29 electrons.

Step11: Answer question 10

Atomic mass = number of protons+number of neutrons = 14 + 14 = 28.

Answer:

1. Atomic number = 8, Atomic mass = 15.999, # of protons = 8, # of electrons = 8, # of neutrons ≈ 8
2. Protons = 22, Neutrons = 26
3. Mass number = 223, Symbol = Fr, Charge = +1
4. Name: rubidium ion, Symbol: $Rb^{+}$
5. Protons = 41, Electrons = 38, Neutrons = 52
6. Protons = 58, Electrons = 54, Neutrons = 82
7. N
8. 7
9. 29
10. 28