Question

awanita is placing items on a shelf that is 200 cm above the ground. she exerts a force of 20 n to lift a box from the floor to the shelf. she does this in 5 s. what is awanitas power output? (power: p = w/t) 4 w 8 w 40 w 800 w

Explanation:

Step1: Calculate work done

Work \(W = F\times d\). The force \(F = 20\ N\) and the distance \(d=200\ cm = 2\ m\). So \(W=20\times2= 40\ J\).

Step2: Calculate power

Power \(P=\frac{W}{t}\), where \(W = 40\ J\) and \(t = 5\ s\). So \(P=\frac{40}{5}=8\ W\).

Answer:

B. 8 W