Question

from ax₄e₀ geometry to ax₃e₁, what is the change in geometry? select one: a. trigonal bipyramidal to tetrahedral b. trigonal pyramidal to tetrahedral c. tetrahedral to trigonal pyramidal d. tetrahedral to trigonal bipyramidal

Explanation:

To solve this, we analyze the VSEPR (Valence Shell Electron Pair Repulsion) theory for molecular geometries:

• For \( \text{AX}_4\text{E}_0 \): The central atom (A) has 4 bonding pairs (X) and 0 lone pairs (E). This corresponds to a tetrahedral geometry (e.g., \( \text{CH}_4 \)).
• For \( \text{AX}_3\text{E}_1 \): The central atom has 3 bonding pairs and 1 lone pair. The lone pair repels bonding pairs, distorting the tetrahedral shape into a trigonal pyramidal geometry (e.g., \( \text{NH}_3 \)).

Thus, the change is from tetrahedral (\( \text{AX}_4\text{E}_0 \)) to trigonal pyramidal (\( \text{AX}_3\text{E}_1 \)).

Answer:

C. Tetrahedral to Trigonal Pyramidal